A business owner claims that the proportion of take out orders is greater than 25%. To test this claim, the owner checks the next 250 orders and determines that 60 orders are take out orders. The following is the setup for this hypothesis test: {H0:p=0.25Ha:p>0.25 Find the test statistic for this hypothesis test for a proportion. Round your answer to 2 decimal places. Provide your answer below: $$

Answer:  -0.37Step-by-step explanation:As per given , we havePopulation proportion : [tex]p=0.25[/tex]Sample size : n= 250Sample proportion : [tex]\hat{p}=\dfrac{60}{250}=0.24[/tex]Test statistic for population proportion :-[tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\=\dfrac{0.24-0.25}{\sqrt{\dfrac{0.25(1-0.25)}{250}}}\\\\=-0.36514837167\ \ \text{(Simplified)}\\\\\approx-0.37 \text{[Rounded to 2 decimal places.]}[/tex]Hence, the test statistic for this hypothesis test for a proportion= -0.37