Find the domain of the function. (Enter your answer using interval notation.)f(x) = x+3/x^2-1

Answer:The domain is:In interval notation: (-infinity,-1) U (-1,1) U (1,infinity)In inequality notation: x<-1 or or -1<x<1 or x>1The problem:Find the domain of f(x) = (x+3)/(x^2-1)Step-by-step explanation:The only thing that needs worrying here is the fraction since you can't divide by 0.So if we solve x^2-1=0 we will find what x cannot be and everything else will be in the domain of the function.Lets solve:x^2-1=0Add 1 on both sides:x^2=1Take square root of both sides:x=1,-1So the domain is all real numbers except x=-1,x=1.The domain is:In interval notation: (-infinity,-1) U (-1,1) U (1,infinity)In inequality notation: x<-1 or -1<x<1 or x>1